find the 3 consecutive terms in ap whose sum is 18 & product is their squares is 140
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x+x+1+x+2=18
3x + 3=18
3x=18-3
3x=15
x=15/3
X=5
X+1=6
X+2=7
3 consecutive numbers are 5,6 and 7
3x + 3=18
3x=18-3
3x=15
x=15/3
X=5
X+1=6
X+2=7
3 consecutive numbers are 5,6 and 7
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