Find the 3-digit number in which each of the three digits is a prime number;and the number is divisible by each of the three digits.with steps
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prime digits are 2,3,5,7
if we take 3 then sum of the digits should be divisible by 3
and if we take 5 then at last it would be 5
So keep 5 at unit digit
now we have to make sum divisible by 3
So 5 + 2 + 3= 10 which is not divisible by 3
so now 5 + 3 +7= 15 which is divisible by 3
So let's check for 375 , it 's not divisible by 7
so interchange first two digits then 735 then it's divisible by 7
hence no is 735
if we take 3 then sum of the digits should be divisible by 3
and if we take 5 then at last it would be 5
So keep 5 at unit digit
now we have to make sum divisible by 3
So 5 + 2 + 3= 10 which is not divisible by 3
so now 5 + 3 +7= 15 which is divisible by 3
So let's check for 375 , it 's not divisible by 7
so interchange first two digits then 735 then it's divisible by 7
hence no is 735
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