Find the 3 digit number whose hundreds place is x, tens value is n and units value is z.
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Answer:
246
Step-by-step explanation:
Let the unit's place digit be x, the tenth place digit be y and the hundredth place digit be z of the three digit number
So the number will be 100z+10y+x
Now given, sum of digits =x+y+z=12......(1)
And y=2x,z=3x
Now using (1)
⇒x+2x+3x=12
⇒6x=12⇒x=2
So y=2x=4 and z=3x=6
Hence the number is =100z+10y+x=642
So the reversed number is 246
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