Question

find the 3 number in a.p whose sum and product are 6and6 respectively​

Answer 1

$\bold\red{Answer:}$

let the three numbers be a-d,a,a+d

a-d+a+a+d=6

3a=6

a=2

a(a-d)(a+d)=6

a(a²-d²)=6

2(4-d²)=6

4-d²=3

d=1 or -1

So numbers are

a-d=1

a=2

a+d=3

or

a-d=3

a=2

a+d=1

So Ap is 3,2,1 or 1,2,3.

hope it helps

☆☆☆