Question

find the 3 number in gp whose sum is 62and their product is 1000​

Answer 1

Answer:

three number is 10,50,2

Step-by-step explanation:

consider the three number is 10,50,2 the sum of three number is,

10+50+2=62

the product of three number is,

10×50×2=1000

there for three number is 10,50,2

Answer 2

Concept

Geometric Progression is a sequence of numbers which share a common  integer such that dividing a term with preceding terms gives this ratio.

This ratio must be non zero. Any number in the sequence can be determined by using this common ratio.

Given

Sum of three terms of the GP is 62 ,Product of three terms is 1000

Find

These three terms which satisfy above conditions.

Solution

let a,ar,ar^2 be the terms of GP

Given that a/r+a+ar =62 and  a/r×a×ar=1000

a(1/r+1+r)=62 and a^3=1000⇒a= 10

⇒ 10(1/r+r+1)=62

⇒ 10(1+r^2+r)=62r

⇒10r^2+10r+10=62r

⇒10r²+52r+10=0

on solving we get r=5 ,

now ,

a/r = 10/5 =2;

a=10;

ar= 50;

Hence ,  the three terms of the GP which satisfies above conditions are 10 , 50 , 2

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