Question

find the 3 term of an AP if their sum is 12 and their product is 28




solve it with explaination​

Answer 1

Step-by-step explanation:

Given:-

sum of three numbers in AP is 12

let take numbers as a-d ,a,a+d

so, a-d+a+a+d=12

product of numbers is 28

Find:-

The numbers

solution:-

sum of numbers is 12

a-d+a+a+d=12

3a=12

a=3/12=4

so, the value of a is 4.

product of numbers is 28

a-d(a) (a+d) =28

(4-d) (4+d) =4/28

2 2

4 - d =7

2

16-d =7

2

-d =7-16

2

-d = -9

d= 9/3

d=3

so, the value of d is 3

first number = a-d = 4-3=1

second number= a = 4

third number = a+d = 4 + 3 = 7

therefore the numbers are 1,4,7

Answer 2

Answer:

Hello

Step-by-step explanation:

please mark me brainlist please