Question

Find the 30th and nth (general term) of the AP 10,7,4,....

Answer 1

Answer:

a=10 , d = -3, a30 =?

a30=a+29d

=10+29(-3)

= 10+(-83)

= -73

a30=-73

Answer 2

Answer:

${\pink{\green{\sf{\therefore a_{30}=-77}}}}$

${\pink{\green{\sf{\therefore a_{n}=13-3n}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• In the given question information given about an A.P.

• We have to find a30th term of given A.P.

• According to given question :

$\underline \bold{given : } \\ \implies a = 10 \\ \implies d = - 3 \\ \\ \underline \bold{to \: find : } \\ \implies a_{30} =? \\ \implies n_{th} = ?$

• We know the formula for nth term.

• Putting values that are given in question.

$\implies a_{30} = a + 29d \\ \implies a_{30} = 10 + 29 \times ( - 3) \\ \implies a_{30} = 10 - 87 \\ \bold{\implies a_{30} = - 77}$

$\implies a_{n} = a + (n - 1)d \\ \implies a_{n} = 10 + (n - 1) \times ( - 3) \\ \implies a_{n} = 10 - 3n + 3 \\ \bold{\implies a_{n} = 13 - 3n}$