Question

find the 30th first term of A.p. 10,7,4 ,1​

Answer 1

Answer:

nth term of an AP is given by

$t_n =a+(n−1)d$

In the given sequence, 'a' = 10, 'd' = -3, 'n' = 30.

So, 30th term =

$t30 =10+(30−1)(−3)$

$t30 = 10−87=−77.$

Answer 2

Answer:

30th term of the A.P: 10, 7, 4, 1 is -77.

Step-by-step explanation:

Given :-

A.P : 10, 7, 4, 1

To find :-

30th term

Solution :-

Using the formula :-

Tₙ = a + (n-1)d

Where,

• a - first term
• n - sum of terms
• d - common difference

Accordingly,

• a - 10
• n - 30
• d = 7 - 10 = -3

Substituting,

• 10 + (30 - 1)-3
• 10 + (29)-3
• 10 - 87
• -77

∴ 30th term of the A.P: 10, 7, 4, 1 is -77.