Question

Find the 30th term of an A.P whose terms and comman difference are 3 and 5 respectively

Answer 1

assuming 3 is the first term then answer is 148

Step-by-step explanation:

a^30 = a + [ n-1 ] d

a30 = 3 + [30 -1 ] 5

a30 = 3 + 29*5

a30 = 3 + 145

a30 = 148

Answer 2

Answer:

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