Question

Find the 30th term of AP 10,7,4...​

Answer 1

[HeY Mate]

$\huge\bold\red{Answer}$

Given

• a (first term) = 10
• d (common difference) = 7-10= -3
• n = 30

To Find

• a30 = ?

Solution

$\tt \implies \: a_{n} = a + (n - 1)d \\ \tt \implies \: a_{30} = 10 + (29) - 3 \\ \tt \implies \: a_{30}= 10 - 87 \\ \tt \implies \: a_{30} = - 77$

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Answer 2

${\huge{\bold{\purple{\bigstar{\boxed{\bf{Question}}}}}}}$

Find the 30th term of AP 10,7,4...

${\huge{\bold{\purple{\bigstar{\boxed{\bf{Answer}}}}}}}$

${\bold{\blue{\boxed{\bf{Given}}}}}$

• first term = a = 10
• common diff. = d = -3
• no. of times =n= 30

${\bold{\blue{\boxed{\bf{To\:find}}}}}$

$\bold{a_{30}}= ???$

${\bold{\blue{\boxed{\bf{ Formulae\:used }}}}}$

$\bold a_n = a + (n-1)d$

${\bold{\blue{\boxed{\bf{ Formulae\:used }}}}}$

$a_{30} = 10 + (30-1)\times - 3$

$a_{30} = 10 + 29 \times -3$

$a_{30} = 10 - 87$

$a_{30} = -77$

${\bold{\blue{\boxed{\boxed{\bf{a_{30} = -77}}}}}}$

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