find the 30th term of thr AP 10,7,4.....
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Answered by
3
given digits=10,7,4......
a1=10,a2=7
difference(d)=a2-a1
=7-10=-3
d=-3
then 30th term=a+29d
=10+29(-3)=10-87=-77
a1=10,a2=7
difference(d)=a2-a1
=7-10=-3
d=-3
then 30th term=a+29d
=10+29(-3)=10-87=-77
Answered by
4
a=10
d=7-10=-3
a30 = a+29d =

d=7-10=-3
a30 = a+29d =
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