Question

find the 30th term of thr AP 10,7,4.....

Answer 1

given digits=10,7,4......
a1=10,a2=7
difference(d)=a2-a1
=7-10=-3
d=-3
then 30th term=a+29d
=10+29(-3)=10-87=-77

Answer 2

30th term of the AP = - 77

Given :

The arithmetic progression 10 , 7 , 4 , . . . .

To find :

30th term of the AP

Concept :

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

Solution :

Step 1 of 3 :

Write down the given progression

Here the given arithmetic progression is

10 , 7 , 4 , . . . .

Step 2 of 3 :

Write down first term and common difference

The arithmetic progression is

10 , 7 , 4 , . . . .

First term = a = 10

Common Difference = d = 7 - 10 = - 3

Step 3 of 3 :

Find 30th term of the AP

30th term of the AP

$\sf = a_{30}$

= a + ( 30 - 1 )d

= a + 29d

= 10 + [ 29 × ( - 3 ) ]

= 10 - 87

= - 77

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