Question

Find the 31" term of an A.P.whose 11th term is 38 and 16th term is 73.​

Answer 1

Answer:

The 31st term of AP is 178

Explanation:

a11 = 38

a+10d = 38

a = 38-10d

a16 = 73

a+15d= 73

substitute the value of a

38- 10d+ 15d = 73

5d = 73-38

5d = 35

d = 7

now, a = 38 - 10d

a = 38 - 10(7)

a = 38 - 70

a = - 32

to find : a31

a31 = a+ 30d

a31 = -32 + 30(7)

= -32 + 210

a31 = 178

therefore, the 31st term of AP is 178