Find the 31 term of an AP whose 13 th term is 38 and 16th term is 73
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2
a13 = 38 = a + 12 d
a16 = 73= a + 15 d
35 = 3d
d = 35÷ 3
a= 38 - 140
= -102
a73= a+ 72 d
= -102 + 72 ( 35 ÷ 3)
= 988 - 102
= 886
Hey mate hope my calculation is right and this will help you
a16 = 73= a + 15 d
35 = 3d
d = 35÷ 3
a= 38 - 140
= -102
a73= a+ 72 d
= -102 + 72 ( 35 ÷ 3)
= 988 - 102
= 886
Hey mate hope my calculation is right and this will help you
Answered by
0
here is the answer my friend
Attachments:
Eustacia:
Cause I hate people supporting stupidity like you
That got me a little irritated ^_^
am I stupid
ooooo really tell me
Nope
I can't insult that word by calling you the same
I can suicide
bye
Oh really ? xD
Enough jokes , relax buddy
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