Find the 31st of an AP exceeds its 10th term by 7 . Find the common difference
Answers
Answered by
0
Answer:
Step-by-step explanation:
Given that the 17th term of an A.P exceeds its 10th term by 7 .
d = ?
⇒a+16d = 1+9d+7
⇒16d-9d = 7
⇒7d = 7
⇒d = 7/7 = 1 .
Therefore , common difference = 1 .
Answered by
0
Answer:
Step-by-step explanation:
a +30d = a+ 9d + 7
21d = 7 ( a and a gets cancelled) (30-9 = 21)
D = 7/21
D = 1/3
Similar questions