Find the 31st term of an
a.P. Whose 10th term is 31 and the 15th term is 66.
Answers
Answered by
8
I hope it will help you
Attachments:
Answered by
5
Answer:
a31 =178
Step-by-step explanation: a10 = 31
a10 = 31
a15 = 66
we have an = a+[n-1]d
a10 = a+9d = 31......1
a15 = a+14d = 66......2
sub 2and1 we get
a+ 14d- a - 9d = 66-31
5d = 35
d = 7
a+[10-1]7 = 31
a= -32
a31 = -32+[31-1]7
a31 = 178
Similar questions