find the 31st term of an A.P. whose 10th term is 38 and 16th term is 74
Answers
Answered by
3
Answer:
164
Step-by-step explanation:
A10 = a + 9d
a + 9d = 38
A16 = a + 15d
a + 15d = 74
On solving both the equations; we get:
d = 6
a = -16
An = a+(n-1)d
A31 = -16 + (30*6)
A31 = -16 + 180
A31 = 164
Answered by
4
Answer:
164 is the 31 st answer
Step-by-step explanation:
see the above attachment for fully solved solution hope it helps
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