Question

Find the 31st term of an AP exceeds its 10th term by 7, find the common difference

Answer 1

see

10th term=a+9d

31st term =a+30d

now 31st term term of an AP exceeds its 10th term by 7,

then

a+30d=a+9d+7

then

a-a+30d-9d=7

therefore

21d=7

then the commen difference d=7/21=1/3

if it is right then mark my ans as a brainliest