Find the 31st term of an AP whose 11th term is 38 and 16th term is 73.
Answers
Answered by
1026
let first term of Ap is a and common difference is d
use formula
tn=a+(n-1) d
now
t11=a+(11-1) d=a+10d=38
same way
t16=a+15d=73
solve this equation then
a=-32 and d=7
now t31=a+30d=-32+210=178
use formula
tn=a+(n-1) d
now
t11=a+(11-1) d=a+10d=38
same way
t16=a+15d=73
solve this equation then
a=-32 and d=7
now t31=a+30d=-32+210=178
Answered by
469
a31=?
a11=38
a16=73
a31=a+30d
a31=-32+30(?)
=-32+210
=178
a+19d=38
a+15d=73
a=-32
d=7
a11=38
a16=73
a31=a+30d
a31=-32+30(?)
=-32+210
=178
a+19d=38
a+15d=73
a=-32
d=7
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