Question

find the 31st term of an AP whose 11th term is 38 and 16th term is 73

step by step explanation plss​

Answer 1

Answer:

this is your answer mate

Answer 2

Answer:

11th term is 38

a11 = a+ 10d

38 = a + 10 d

38 - 10d = a (1)

16th term is 73

a16 = a +15d

73 = a + 15 d

73 - 15 d = a (2)

from 1 and 2 equation

38 - 10d = 73- 15 d

15 d - 10 d = 73 - 38

5d = 35

d = 7

take equation 1 and put the value of d

38 - 10 * 7 = a

a= 32

now 31st term

a31 = a + 30d

a31 =241