- Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.
Answers
Answered by
1
Answer:
141.4375
Step-by-step explanation:
because 1 term =4.5625 multiplied by 31
Answered by
1
Answer:
31st term of an AP is 178
Step-by-step explanation:
a = first term and d = common difference
11th term of an AP is = a + 10d = 38 ............1
16th term of an AP is = a+15d = 73..............2
subtract equation 1 from 2
a + 15d - ( a + 10d) = 73-38
a + 15d - a - 10d = 35
5d = 35
d = 7 ...........3
put equation 3 into 1
a+ 10*7 = 38
a = 38-70
a = - 32
31st term of an AP is = a + 30d
= -32 + 30*7
= 210 - 32
= 178
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