Math, asked by poojamishra99108, 13 days ago


Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.

Answers

Answered by vandan80
2

Step-by-step explanation:

a31 = ?

a11 = 38

a16 = 73

a+10d = 38

a+15d = 73

----------------

-5d = -35

d=7

so, put d in eqn 1,

a+10(7) = 38

a+70=38

a= -32

a31 = a+30d

= -32+210

=178

Hope it helps you

thank you

Answered by Anonymous
3

Answer:

Ur ansr mate...

Step-by-step explanation:

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