Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73
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Step-by-step explanation:
an=a+(n-1)d
38=a+(11-1)d
38=a+10d
a+10d=38------------------------------(1)
73=a+(16-1)d
73=a+15d
a+15d=73--------------------------------(2)
subtracting 1 from 2
a+15d=73
a+10d=38
---------------
0+5d=35
d=35/5
d=7
appling d value in 1
a+70=38
a=38-70
a=-32
31ts term will be
-32+(31-1)7=
-32+210=
178
therefore,
31st value is 178
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