Math, asked by alphashahkhan1879, 1 year ago

Find the 31st term of an ap whose 11th term is 38and the 16th teem is 73 with full answer

Answers

Answered by abhi569
3
11th  term = 38 
a + 10d =38 
a = 38 - 10d       -------1equation

======================

16th term = 73 
a + 15d =73 

putting the value of a from 1equation


38 - 10d  + 15d = 73 

5d  = 73 - 38 

5d = 35 

 d = 35/5 
     = 7 

putting the value of 7 in 1equation, 38 -10d = a
                                                        38 - 10(7) = a 
                                                         38 - 70 = a 
                                                          -32       = a 


=----------------------------------------

31st term = a + 30d
                = -32 + 30(7)
                = -32 + 210
                =  178


i hope this will help you

(-:
Answered by Bhavanavindamuri
1
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