find the 31st term of an ap whose 11th term is 88 and 16 term is 73 which term of this series will be the 1th negative term ?
Answers
Answered by
16
Answer:
11th term=88
An=88, n=11
An=a+(n-1)d
A11=a+(11-1)d
88=a+10d--eq1
16th term=73
An=73, n=16
An=a+(n-1)d
A16=a+(16-1)d
73=a+15d--eq2
Add eq1and eq2, we get
5d=(-15)
d=(-15)/5
d=(-3)
Substitute d=(-3) in eq1
a+10d=88
a+10(-3)=88
a-30=88
a=88+30
a=118
31st term
a=118, d=(-3)
An=a+(n-1)d
A31=118+(31-1)(-3)
A31=118+(30)(-3)
A31=118-90
A31=28
Therefore, the 31st term of an ap is 28.
Answered by
4
31st term = 28
41st term is first negative term of the following AP
Full answer is in the above attachment!
Hope it helps...!
Have a great day ahead..!
Attachments:
Similar questions