Question

Find the 31st term of Ap 9,17,25--must be taken to give sum of 636​

Answer 1

Step-by-step explanation:

where is the sum of first term to nth term of the AP, a is the first term, d is the common difference and n is the number of terms of AP. In the given Question, sum of APs is 636. Hence, Number of terms of the AP [ 9 , 17 , 25 ] which are required to make the sum of 636 is 12.