find the 31st term of ap whoose 11 term is 10 and 16 term is 20
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Answered by
10
A31=?
a11=38
a16=73
a31=a+30d
a31=-32+30(?)
=-32+210
=178
a+19d=38
a+15d=73
a=-32
d=7
Answered by
1
Answer:
Step-by-step explanation:
Given 11th term=10
a+10d=10
16th term=20
a+15d=20
from both equations
5d=10
d=2
and a=-10
31st term=a+30d
= -10+30(2)
= 60-10
= 50
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