Math, asked by anjalisharma510, 8 months ago

find the 31st term of ap whoose 11 term is 10 and 16 term is 20

Answers

Answered by Anonymous
10

A31=?

a11=38

a16=73

a31=a+30d

a31=-32+30(?)

=-32+210

=178

a+19d=38

a+15d=73

a=-32

d=7

Answered by pawanbhavanam2
1

Answer:

Step-by-step explanation:

Given 11th term=10

a+10d=10

16th term=20

a+15d=20

from both equations

5d=10

d=2

and a=-10

31st term=a+30d

= -10+30(2)

= 60-10

= 50

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