Math, asked by rampraveshprajapati9, 5 months ago

find the 31th term of an AP whose 11th term is 38 and the 16th Term is 73

Answers

Answered by aadya4836

1

Answer:

Let the 31st term be a31

a11=38

a16=73

a11 = a+ 10d

38=a + 10d

a=38-10d

a16= a+ 15d

73= a+15d

73= 38-10d+15d

5d=35

d= 7

a= -32

a31= a+30d

a31= -32+ 210

a31 = 178

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