Question

find the 32nd term of the following series3,7,11​

Answer 1

Answer:

and the 32nd term of the series is 127

Step-by-step explanation:

a+(n-1)d

a=3, n=32, d=4

3+(32-1)4

3+31×4

3+124

127

Answer 2

Answer:

3,7,11,15,19,23,27,31,35,39,43,47,51,55,59,63,67,71,75,79,83 ,87,91,85,89,93,97,101,105,109,113,117,121