Math, asked by DynamicDhruv1025, 10 months ago

Find the 33rd term of the sequence 3,8,9,13,15,18,21,23,.......

Answers

Answered by FNC00
0

Answer:

Ans..163

Step-by-step explanation:

a=3

d=5

T33=a+(n-1)d

=3+32X5

=3+160

=163..

Answered by asmit2003kumar
0

Answer:

99

Step-by-step explanation:

So if we consider the odd number terms in this sequence .ie. -
1st term = 3  (3*1)
3rd term = 9  (3*3)
5th term = 15  (3*5)
7th term = 21 (3*7)

We can identify the general trend in case of odd terms..
Since 33rd term is also an odd term we can say

ans- 99 (3*33)

Similar questions