Find the 35th term of an ap 6,9,12,15
Answers
Answer:
108
Step-by-step explanation:
an= a+(n-1)d
= 6+(35-1)*3
= 6+102=108
therefore the 35th term of this A.P is 108
In the above Question , the following AP series is given -
Series -
6, 9, 12 , 15 , .....
To find -
Find the 35th term of this series .
Solution -
Here ,
The given series is -
6, 9, 12, 15 , ....
Here , the initial term , a is 6 .
The common difference , d -
=> 9 - 6 = 12 - 9 = 15 - 12 = d
=> d = 3 .
Now , we know that the n th term of an AP can be expressed as -
=> a + ( n - 1 ) d
=> 6 + ( n - 1 ) 3
=> 6 + 3n - 3
=> 3 n + 3 .
Now , we have to find the 35th term. .
35th term -
=> 3 × 35 + 3
=> 105 + 3 .
=> 108 .
Thus , the 35 th term of this given series is 108 .
This is the required answer .
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