Find the 35th term of the arithmetic sequence 5, 17, 29, 41
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Answered by
12
Heya !!!
AP = 5 , 17 , 29.....
Here,
First term (A) = 5
Common Difference (D) = 17 - 5 = 12
Therefore,
35th term = A + 34D
=> 5 + 34 × 12
=> 5 + 408
=> 413
★ HOPE IT WILL HELP YOU ★
AP = 5 , 17 , 29.....
Here,
First term (A) = 5
Common Difference (D) = 17 - 5 = 12
Therefore,
35th term = A + 34D
=> 5 + 34 × 12
=> 5 + 408
=> 413
★ HOPE IT WILL HELP YOU ★
RehanAhmadXLX:
:-)
Answered by
13
Hope this helps you ☺☺☺
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thnq
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