Question

Find the 37th term of the A.P. √x, 3√x, 5√x,..........

Answer 1

Answer:

Hope it helps!!!

Answer 2

The 37th term of an A.P is $73\sqrt{x}$

Step-by-step explanation:

Given : A.P. $\sqrt{x},\ 3\sqrt{x},\ 5\sqrt{x},\ ..........$

To find : The 37th term ?

Solution :

In an A.P. $\sqrt{x},\ 3\sqrt{x},\ 5\sqrt{x},\ ..........$

The first term is $a=\sqrt{x}$

The common difference is $d=3\sqrt{x}-\sqrt{x}=2\sqrt{x}$

The nth term of an A.P is given by,

$a_n=a+(n-1)d$

The 37th term of an A.P is

$a_{37}=\sqrt{x}+(37-1)(2\sqrt{x})$

$a_{37}=\sqrt{x}+(36)(2\sqrt{x})$

$a_{37}=\sqrt{x}+72\sqrt{x}$

$a_{37}=73\sqrt{x}$

Therefore, the 37th term of an A.P is $73\sqrt{x}$

#Learn more

Find 37th and 101 th term of the following A.P 2,5,8,11, .....

https://brainly.in/question/7662656