Question

find the 3rd term in the expansion of (2x²+3/2x)⁸​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER

(32x2−2x3)12

middle term be r=7

12C7(32x2)5.(2x−3)7

−12C725.35x1027.x737

−12C72232.x3

−5!7!12!49.x3

5×4×3×2×412×11×10×9×8×9.x3

−1782x3

I HOPE THIS ANSWER MAY HELPS YOU...........

Answer 2

Answer:

-1782x3 is the answer ....