Find the 3rd vertex of an isosceles triangle if 2 of its vertices are (-6,0) and (14,8)
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Answer:
we label them A(13,-2) B(9-8) and C(5-2)
The distance between A and B:
13
⇒
9
=
4
−
2
⇒
−
8
=
6
4
2
+
6
2
=
52
so the distance is
√
52
The distance between B and C:
9
⇒
5
=
4
−
8
⇒
−
2
=
6
4
2
+
6
2
=
52
the distance is
√
52
The distance between A and C is 8 as they are both on -2 for
y
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