find the 4 consecutive numbers
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✪ Question ✪
The sum of four consecutive numbers is 230. Find the 4 consecutive numbers .
✪ Given ✪
Sum = 230
✪ To find ✪
The 4 consecutive numbers.
✪ Solution ✪
Let the numbers are x, (x+1), (x+2) and (x+3).
According to condition,
x + (x+1) + (x+2) + (x+3) = 230
⇒x + x + 1 + x + 2 + x + 3 = 230
⇒4x + 6 = 230
⇒4x = 230 - 6
⇒4x = 224
⇒x = 224/4
⇒x = 56
✪ Hence ✪
- x = 56
- (x+1) = (56+1) = 57
- (x+2) = (56+2) = 58
- (x+3) = (56+3) = 59
✪ Therefore ✪
The 4 consecutive numbers are 56, 57, 58 and 58.
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✪ Verification ✪
x + (x+1) + (x+2) + (x+3) = 230
⇒56 + 57 + 58 + 59 = 230
⇒230 = 230
So, L.H.S = R.H.S.
Hence, verified.
๑ Hope this helps you. ๑
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