Find the 4-digit smallest
number which when divided by
12, 15, 25, 30 leaves no
remainder?
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ANSWER IS 1020
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Solution :-
Finding LCM of 12, 15, 25 and 30 first we get,
→ 12 = 2 * 2 * 3
→ 15 = 3 * 5
→ 25 = 5 * 5
→ 30 = 2 * 3 * 5
So,
→ LCM = 2 * 2 * 3 * 5 * 5 = 300
then,
→ Smallest four digit number = 1000
therefore, smallest four digit number near 1000 which is multiple of 300 will be,
→ 300 * 4 = 1200 .
Hence, 1200 is the required smallest 4 digit number .
Learn more :-
let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46
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