Math, asked by bondalapunaresh2000, 7 days ago

Find the 4-digit smallest
number which when divided by
12, 15, 25, 30 leaves no
remainder?

Answers

Answered by RajdeepSangui
0

ANSWER IS 1020

DOING MY ANSWER 20 WORDS LONG

Answered by RvChaudharY50
0

Solution :-

Finding LCM of 12, 15, 25 and 30 first we get,

→ 12 = 2 * 2 * 3

→ 15 = 3 * 5

→ 25 = 5 * 5

→ 30 = 2 * 3 * 5

So,

→ LCM = 2 * 2 * 3 * 5 * 5 = 300

then,

→ Smallest four digit number = 1000

therefore, smallest four digit number near 1000 which is multiple of 300 will be,

→ 300 * 4 = 1200 .

Hence, 1200 is the required smallest 4 digit number .

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

p...

https://brainly.in/question/40043888

Similar questions