find the 40th term of an A.P whose 12th term is 45 and 17th term is 80?
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EXPLANATION.
=> 12th term is = 45
=> 17th term is = 80
To find 40th term of an Ap.
Formula of Nth term of an Ap.
=> An = a + ( n - 1 ) d
=> 12th term = 45
=> a + 11d = 45 ...... (1)
=> 17th term = 80
=> a + 16d = 80 ..... (2)
From equation (1) and (2)
we get,
=> -5d = -35
=> d = 7
put the value of d = 7 in equation (1)
we get,
=> a + 11(7) = 45
=> a + 77 = 45
=> a = -32
40th term of an Ap.
=> a + 39d
=> -32 + 39(7)
=> -32 + 273
=> 241
Therefore,
40th term of an Ap = 241
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