find the 40th term of an A.P whose 12th term is 45 and 17th term is 80?
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1
Answer:
a40=?
a12=45 and a17=80
or. a+11d=45
and a+16d=80
by solving this equation
d=7 and a will be 45-77= -32
a40= a+39d
-32+39(7)
-32+273
a40=241
Answered by
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Answer:
maths
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