Question

find the 40th term of an Ap whose
12th term is 47. and the 18th term is 71​

Answer 1

ans: as 12th term=47

we can write it as a+11d=47-a eq (where a is first term and d is common difference

similarily

we can write 18th term as a+17d=71-b eq

subtract a eq from b eq

we get d=4

a=3

40th term=a+(40-1)d

therefore 3+(39)4=3+156=159

hence 40th term is 159

thanku

Answer 2

Answer:

hope it helps............