find the 40th term of the Ap - 12,-5,2,9......
plzzz anyone fast give me answer.
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Hey here is your answer.
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n=40 a=-12
d=a1-a2
-5-(-12)=-7
an=a+(n-2)d
an=-12+(-12-2)-7
an=-12+(-14)-7
an=12+98
an=110
rajatverma20:
A= - 12 d= 7 : T40 = a+(n-1)d . T40= a+39d . - 12 + 39(7) . - 12+273= T40= 261
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