Question

Find the 41st term of the AP :-2 ; 2 ; 6 ; 10 ;..... .formula is (an = a (n-1) d) .​

Answer 1

SOLUTION:-

The given AP is -2,2,6,10.............

its first term =-2 and common differences ={2-(-2)}=4

a= -2 and d= 4

The nth term of the AP is given by

Tn=a+(n-1)d

we have find 41st term so n=41

T41=a+(41-1)d

=a+40d

= -2+40×4 [:- a= -2 and d=4]

= -2+160

=158

Hence,41st term=158