find the 45th term of an AP whose 11tg term is 38 and the 16th term is 73
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It is given that,
11th term = 38
a+10d= 38...........(1)
also,
16th term = 73
a+ 15d= 73...........(2)
from (1) and (2),
a + 15d= 73
a+ 10d= 38
5d = 35
d= 35/5
d= 7
putting the value of d in (1)
a + 10(7) = 38
a+ 70 = 38
a = 38-70
a= - 32
Now, the 45th term = a+ 44d
= -32+44(7)
= -32 + 308
= 276
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