Find the 4th and 8th term of the series 6, 4, 3, … .....???
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Answered by
12
Answer:
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Step-by-step explanation:
=> Consider 1/6, 1/4, 1/3, ...
=> Here T2 – T1 = T3 – T2 = 1/12
=> Therefore 1/6, 1/4, 1/3 is in A.P.
=> 4th term of this Arithmetic Progression = 1/6 + 3 × 1/12 = 1/6 + 1/4 = 5/12,
=> Eighth term = 1/6 + 7 × 1/12 = 9/12.
=> Hence
=> the 8th term of the H.P. = 12/9 = 4/3
and
=> the 4th term = 12/5.
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Answered by
8
Explanation:=
Consider 1/6, 1/4, 1/3, ...
Here T2 – T1 = T3 – T2 = 1/12
Therefore 1/6, 1/4, 1/3 is in A.P.
4th term of this Arithmetic Progression = 1/6 + 3 × 1/12 = 1/6 + 1/4 = 5/12,
Eighth term = 1/6 + 7 × 1/12 = 9/12.
Hence the 8th term of the H.P. = 12/9 = 4/3 and the 4th term = 12/5.
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