Question

find the 4th term from the end of the AP -11,-8,-5,........,49

Answer 1

See the image for solution.

Answer 2

Answer:

$Fourth\:term\:the \:last \:of\\the \:A.P = 40$

Step-by-step explanation:

Given A.P:

-11,-8,-5,.….,49

first term (a) = -11,

$Common\: difference (d)\\=a_{2}-a_{1}\\=-8-(-11)\\=-8+11\\=3$

Now,

Rearranging the terms , from last to first ,we get

49,46,...,-5,-8,-11

first term (a) = 49,

d = 46-49 = -3

$Fourth\:term (a_{4})=a+3d$

$=49+3\times (-3)\\=49-9\\=40$

Therefore,

$Fourth\:term\:the \:last \:of\\the \:A.P = 40$

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