Question

Find the 4th term from the end of the AP -11, -8, -5, ........,49?​

Answer 1

Answer:

46

Step-by-step explanation:

please Mark as the brainliest

Answer 2

Answer:

$\bigstar{\bold{Fourth\:term\:from\:end=40}}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• A.P is -11, -8 , -5.....49

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• The 4th term from the end of the A.P

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Here we have to find the A.P from the end of the series.

→ Reversing the A.P we can find the fourth term from the start of the A.P

→ Reversed A.P is,

  49,......-5, -8 , -11

→ First find the common difference (d) of the A.P

  d = -8 + 5 = -3

→ Hence the common difference of the A.P is -3

→ The fourth term of an A.P is given by the formula,

  a₄ = a₁ + 3d

  where a₁ = 49 , d = -3

→ Substituting the datas we get,

  a₄ = 49 + 3 × -3

  a₄ = 49 - 9

  a₄ = 40

→ Hence the fourth term from the end of the given series is 40

$\boxed{\bold{Fourth\:term\:from\:end=40}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The nth term of an A.P is given by,

  $a_n=a_1+(n-1)\times d$

→ Sum of n terms of an A.P is given by,

   $S_n=\dfrac{n}{2}(2a_1+(n-1)\times d)$

  $S_n=\dfrac{n}{2}(a_1+a_n)$