Question

Find the 4th term from the end of the g.p. 2/27, 2/9, 2/3, ………,162.

Answer 1

Given:-

$\frac{2}{27} . \frac{2}{9} . \frac{2}{3} ........162.$

To find :-

The 4th term from last.

Solution :-

$\frac{2}{27} . \frac{2}{9} . \frac{2}{3} ........162.$

$a = \frac{2}{27}$

$r = \frac{2}{27} \times \frac{27}{2}$

$r = 3$

$the \: forth \: term \: last \: is \:$

$l \times {( \frac{1}{r})}^{n - 1}$

$162 \times \{frac{1}{3}}^{3}$

$= 6$

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