Question

find the 4th term of ap root 2, root 8,root 18​

Answer 1

Answer:

Step-by-step explanation:

d=√8-√2=2√2-√2=√2

discriminant=√2, first term=√2, second term=√8=2√2 and third term=√18=3√2

Then, fourth term=third term+discriminant

=3√2+√2=4√2=√32

Answer 2

Answer:

$n4 = ( \sqrt{2} (4 - 1) \sqrt{6}$

$= \sqrt{2} \times 3 \times \sqrt{6}$

$= 2 \times 3$

$= 6$