Question

Find the 5 th term from the end of the A.P : 17,14,11, ---------- -14.​

Answer 1

Answer:

-2

Step-by-step explanation:

AP is 17,14......-14

reverse the AP

-14;-11;-8....17

a=t1=-14, t2=-11

$d = t2 - t1 \: \\ \: \: \: \: = - 11 - ( - 14) \\ \: : \: \: \: = - 11 + 14\\ \: d = 3$

take the formula of tn,

$tn = a + (n - 1)d \\ t5 = - 14 + (5 - 1)( 3) \\ t5 = - 14 + 4( 3) \\ t5 = - 14 + 12 \\ t5 = -2$

so the fifth term of AP

-2