find the 53th term of the arithmetic sequence 27,11,-5
Answers
Answered by
0
Answer:
a = 2
d = 7-2 = 5
n =53
a53 = a +(n-1) d
a53 = 2+(53-1)5
a53 = 2+52×5
a53 = 2+260
a53= 262
Answered by
0
Answer:
answer is (-805)
Step-by-step explanation:
a = 27
d=11 - 27 = - 5- 11
= -16
a53 =?
a53 = a + 52d
27 + 52× -16
27- 832
= - 805
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